2021高考化学一轮复习章末排查练6化学反应与能量转化含解析鲁科版2

来源:监理师 发布时间:2021-05-09 点击:

 2021-4-29

 20XX 年复习资料

 教学复习资料

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 级:

  科

 目 :

 章末排查练( ( 六)

 化学反应与能量转化

 (本栏目内容,在学生用书中以独立形式分册装订!) 排查点一 热化学方程式的再书写 1.沼气是一种能源,它的主要成分是 CH 4 ,常温下,0.5 mol CH 4 完全燃烧生成 CO 2 (g)和液态水时,放出 445 kJ 热量,则热化学方程式为 ________________________________________________________________________ ________________________________________________________________________。

 答案:

 CH 4 (g)+2O 2 (g)===CO 2 (g)+2H 2 O(l)

 Δ H =-890 kJ·mol-1

 2.已知 H 2 S 完全燃烧生成 SO 2 (g)和 H 2 O(l),H 2 S 的燃烧热为 a

 kJ·mol-1 ,写出 H2 S的燃烧热化学方程式 ________________________________________________________________________ ________________________________________________________________________。

 答案:

 2H 2 S(g)+3O 2 (g)===2SO 2 (g)+2H 2 O(l)

 Δ H =-2 a

 kJ·mol-1

 3.已知 H—H 键能 436 kJ·mol-1 ,H—N 键能 391 kJ·mol -1 ,NN 键能 945.6 kJ·mol -1 ,试写出 N 2 和 H 2 反应生成 NH 3 的热化学方程式 ________________________________________________________________________ ________________________________________________________________________ ________________________________________________________________________。

 答案:

 N 2 (g)+3H 2 (g)===2NH 3 (g)

 Δ H =-92。4 kJ·mol-1

 4.已知 错误! !N 2 (g)+ 错误! !H 2 (g)===N(g)+3H(g)

 Δ H 1 =+ a

 kJ·mol-1

 N(g)+3H(g)===NH 3 (g) Δ H 2 =- b

 kJ·mol-1

 NH 3 (g)===NH 3 (l)

 Δ H 3 =- c

 kJ·mol-1

 写出 N 2 (g)和 H 2 (g)反应生成液氨的热化学方程式 ________________________________________________________________________ ________________________________________________________________________。

 答案:

 N 2 (g)+3H 2 (g)===2NH 3 (l)

 Δ H =-2( b + c - a )

 kJ·mol-1

 5.已知:①HF(aq)+OH- (aq)===F - (aq)+H2 O(l)

 Δ H =-67。7 kJ·mol-1

 ②H+ (aq)+OH - (aq)===H2 O(l)

 Δ H =-57。3 kJ·mol-1

 试写出 HF 电离的热化学方程式 ________________________________________________________________________ ________________________________________________________________________. 答案:

 HF(aq)⇌F- (aq)+H + (aq)

 Δ H =-10.4 kJ·mol-1

 6.SF 6 是一种优良的绝缘气体,分子结构中,只存在 S—F 键,已知 1 mol S(s)转化为气态硫原子吸收能量 280 kJ,F—F 键能为 160 kJ·mol-1 ,S—F 键能为 330 kJ·mol -1 ,试写出 S(s)和 F 2 (g)反应生成 SF 6 (g)的热化学方程式 ________________________________________________________________________ ________________________________________________________________________。

 答案:

 S(s)+3F 2 (g)===SF 6 (g)

 Δ H =-1 220 kJ·mol-1 排查点二 电池电极反应式或总反应式的再书写 1.用惰性电极电解下列溶液 (1)NaCl 溶液 阴极: ________________________________________________________________________; 阳极:

 ________________________________________________________________________; 总反应式:

 ________________________________________________________________________。

 (2)CuSO 4 溶液 阴极:

 ________________________________________________________________________; 阳极:

 ________________________________________________________________________; 总反应式:

 ________________________________________________________________________。

 答案:

 (1)2H+ +2e - ===H2 ↑ 2Cl- -2e - ===Cl2 ↑ 2NaCl+2H 2 O 错误! !2NaOH+H 2 ↑+Cl 2 ↑ (2)2Cu2+ +4e - ===2Cu 4OH- -4e - ===2H2 O+O 2 ↑ 2CuSO 4 +2H 2 O 错误! !2Cu+2H 2 SO 4 +O 2 ↑

 2.用铜作电极电解下列溶液 (1)H 2 O 阴极:

 ________________________________________________________________________; 阳极:

 ________________________________________________________________________; 总反应式:

 ________________________________________________________________________. (2)H 2 SO 4 溶液 阴极:

 ________________________________________________________________________; 阳极: ________________________________________________________________________; 总反应式:

 ________________________________________________________________________。

 (3)NaOH 溶液 阴极:

 ________________________________________________________________________; 阳极:

 ________________________________________________________________________; 总反应式:

 ________________________________________________________________________. 答案: (1)2H+ +2e - ===H2 ↑ Cu-2e- ===Cu 2+

 Cu+2H 2 O 错误! !Cu(OH) 2 +H 2 ↑ (2)2H+ +2e - ===H2 ↑ Cu-2e- ===Cu 2+

 Cu+H 2 SO 4 错误! !CuSO 4 +H 2 ↑ (3)2H 2 O+2e- ===H2 ↑+2OH-

 Cu-2e- +2OH - ===Cu(OH)2

 Cu+2H 2 O 错误! !Cu(OH) 2 +H 2 ↑ 3.用 Al 作电极电解下列溶液 (1)H 2 SO 4 溶液 阴极:

 ________________________________________________________________________; 阳极:

 ________________________________________________________________________; 总反应式:

 ________________________________________________________________________。

 (2)NaOH 溶液 阴极:

 ________________________________________________________________________; 阳极: ________________________________________________________________________; 总反应式:

 ________________________________________________________________________. 答案:

 (1)6H+ +6e - ===3H2 ↑ 2Al-6e- ===2Al 3+

 2Al+3H 2 SO 4 错误! !Al 2 (SO 4 ) 3 +3H 2 ↑ (2)6H 2 O+6e- ===3H2 ↑+6OH-

 2Al-6e- +8OH - ===2[Al(OH)4 ]-

 2Al+6H 2 O+2NaOH 错误! !2Na[Al(OH) 4 ]+3H 2 ↑ 4.铁镍电池(负极-Fe,正极—NiO 2 ,电解液-KOH 溶液)

 已知 Fe+NiO 2 +2H 2 O 错误! !Fe(OH)

 2 +Ni(OH)

 2 ,则:

 负极:

 ________________________________________________________________________; 正极:

 ________________________________________________________________________. 阴极:

 ________________________________________________________________________; 阳极:

 ________________________________________________________________________。

 答案:

 Fe-2e- +2OH - ===Fe(OH)2

 NiO 2 +2H 2 O+2e- ===Ni(OH)2 +2OH-

 Fe(OH) 2 +2e- ===Fe+2OH -

 Ni(OH)

 2 -2e- +2OH - ===NiO2 +2H 2 O 5.LiFePO 4 电池(正极-LiFePO 4 ,负极-Li,含 Li+ 导电固体为电解质) 已知 FePO 4 +Li 错误! !LiFePO 4 ,则

 负极: ________________________________________________________________________; 正极:

 ________________________________________________________________________. 阴极:

 ________________________________________________________________________; 阳极:

 ________________________________________________________________________. 答案: Li-e- ===Li +

 FePO 4 +Li+ +e - ===LiFePO4

 Li+ +e - ===Li LiFePO 4 -e- ===FePO4 +Li+

 6.高铁电池(负极—Zn,正极—石墨,电解质为浸湿的固态碱性物质) 已知:3Zn+2K 2 FeO 4 +8H 2 O 错误! !3Zn(OH)

 2 +2Fe(OH)

 3 +4KOH,则:

 负极: ________________________________________________________________________; 正极:

 ________________________________________________________________________。

 阴极:

 ________________________________________________________________________; 阳极: ________________________________________________________________________。

 答案: 3Zn-6e- +6OH - ===3Zn(OH)2

 2FeO 错误! !+6e- +8H2 O===2Fe(OH) 3 +10OH-

 3Zn(OH) 2 +6e- ===3Zn+6OH -

 2Fe(OH)

 3 -6e- +10OH - ===2FeO 错误! !+8H 2 O 7.氢氧燃料电池 (1)电解质是 KOH 溶液(碱性电解质) 负极: ________________________________________________________________________; 正极:

 ________________________________________________________________________; 总反应方程式: ________________________________________________________________________.

 (2)电解质是 H 2 SO 4 溶液(酸性电解质)

 负极: ________________________________________________________________________; 正极:

 ________________________________________________________________________; 总反应方程式:

 ________________________________________________________________________。

 (3)电解质是 NaCl 溶液(中性电解质)

 负极:

 ________________________________________________________________________; 正极:

 ________________________________________________________________________; 总反应方程式:

 ________________________________________________________________________. 答案: (1)2H 2 -4e- +4OH - ===4H2 O O 2 +2H 2 O+4e- ===4OH -

 2H 2 +O 2 ===2H 2 O (2)2H 2 -4e- ===4H +

 O 2 +4H+ +4e - ===2H2 O 2H 2 +O 2 ===2H 2 O (3)2H 2 -4e- ===4H +

 O 2 +2H 2 O+4e- ===4OH -

 2H 2 +O 2 ===2H 2 O 8.甲烷燃料电池(铂为两极,正极通入 O 2 和 CO 2 ,负极通入甲烷,电解液有三种) (1)电解质是熔融碳酸盐(K 2 CO 3 或 Na 2 CO 3 )

 正极: ________________________________________________________________________; 负极: ________________________________________________________________________; 总反应方程式:

 ________________________________________________________________________。

 (2)酸性电解质(电解液为 H 2 SO 4 溶液)

  正极: ________________________________________________________________________;

 负极:

 ________________________________________________________________________; 总反应方程式:

 ________________________________________________________________________. (3)碱性电解质(电解液为 KOH 溶液)

 正极: ________________________________________________________________________; 负极:

 ________________________________________________________________________; 总反应方程式: ________________________________________________________________________。

 答案: (1)2O 2 +8e- +4CO2 ===4CO 错误! ! CH 4 -8e- +4CO 错误! !===5CO 2 +2H 2 O CH 4 +2O 2 ===CO 2 +2H 2 O (2)2O 2 +8e- +8H + ===4H2 O CH 4 -8e- +2H2 O===CO 2 +8H+

 CH 4 +2O 2 ===CO 2 +2H 2 O (3)2O 2 +8e- +4H2 O===8OH-

 CH 4 -8e- +10OH - ===CO 错误! !+7H 2 O CH 4 +2O 2 +2OH- ===CO 错误! !+3H 2 O 9.甲醇燃料电池 (1)碱性电解质(铂为两极,电解液为 KOH 溶液)

 正极:

 ________________________________________________________________________; 负极:

 ________________________________________________________________________; 总反应方程式:

 ________________________________________________________________________。

 (2)酸性电解质(铂为两极,电解液为 H 2 SO 4 溶液)

 正极:

 ________________________________________________________________________; 负极: ________________________________________________________________________; 总反应方程式:

 ________________________________________________________________________。

 答案: (1)3O 2 +12e- +6H2 O===12OH-

 2CH 3 OH-12e- +16OH - ===2CO 错误! !+12H 2 O 2CH 3 OH+3O 2 +4KOH===2K 2 CO 3 +6H 2 O (2)3O 2 +12e- +12H + ===6H2 O 2CH 3 OH-12e- +2H2 O===12H+ +2CO2

 2CH 3 OH+3O 2 ===2CO 2 +4H 2 O 10.CO 燃料电池(总反应方程式均为 2CO+O 2 ===2CO 2 )

 (1)熔融盐(铂为两极,Li 2 CO 3 和 Na 2 CO 3 的熔融盐作电解质,CO 为负极燃气,空气与 CO 2的混合气为正极助燃气)

 正极:

 ________________________________________________________________________; 负极:

 ________________________________________________________________________。

 (2)酸性电解质(铂为两极,电解液为 H 2 SO 4 溶液)

 正极:

 ________________________________________________________________________; 负极: ________________________________________________________________________。

 答案:

 (1)O 2 +4e- +2CO2 ===2CO 错误! ! 2CO+2CO 错误! !-4e- ===4CO2

 (2)O 2 +4e- +4H + ===2H2 O 2CO-4e- +2H2 O===2CO 2 +4H+

 ...

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